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Study finds Jacksonville most affordable big city in Florida

Jacksonville ranks No. 37 nationwide, according to study

JACKSONVILLE, Fla. – A study by the financial technology company, SmartAssest, found that Jacksonville is the most affordable big city in Florida and ranks among the most affordable cities nationwide. 

The cities were measured on factors that include property taxes, homeowners insurance and mortgage payments relative to median income. 

According to the study, Jacksonville ranks No. 1 among Florida's biggest cities and No. 37 nationwide in affordability. 

According to SmartAsset's website, the most affordable cities were those in which total housing costs on an average house accounted for the smallest proportion of the city's median income.

Click here to learn more about SmartAssest's methodology and an interactive map.